Project Euler

Problem 16: Power Digit Sum

2¹⁵ = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26. What is the sum of the digits of the number 2¹⁰⁰⁰?

The Catch

How to store and quickly calculate extremely large numbers.

The Light

Use Java's BigInteger class as discussed in Problem 13. Then parse the result into an array of digit-character to calculate their sum.

The Code

import java.math.BigInteger;

public class Problem16
{
  public static void main(String[] args)
  {
    BigInteger n = new BigInteger("2");
    n = n.pow(1000);
    System.out.println("2^1000 = " + n);

    String s = n.toString();
    int sum = 0;
    for(int i = 0; i < s.length(); i++)
    {
      sum += Character.getNumericValue(s.charAt(i));  
    }
    System.out.println("Sum of all digits = " + sum);
 }
}